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Election in Michigan
1860 United States presidential election in Michigan
County Results
Lincoln
50-60%
60-70%
70-80%
Douglas
50-60%
60-70%
70-80%
The 1860 United States presidential election in Michigan took place on November 6, 1860, as part of the 1860 United States presidential election . Voters chose six representatives, or electors, to the Electoral College , who voted for president and vice president .[1]
Michigan was won by the Republican nominee, Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine . They defeated the Democratic nominee, Senator Stephen A. Douglas of Illinois and his running mate with 41st Governor of Georgia Herschel V. Johnson .[1] Lincoln won the state by a margin of 15.24%.
The 1860 presidential election in Michigan began a trend in which the state would vote the same as Pennsylvania , as the two states would vote in lockstep with each other on all but three occasions since Lincoln’s victory - 1932 , 1940 , and 1976 .
Results [ edit ]
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